p^2-40p-50=0

Solution for p^2-40p-50=0 equation:

p^2-40p-50=0

a = 1; b = -40; c = -50;
Δ = b2-4ac
Δ = -402-4·1·(-50)
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-30\sqrt{2}}{2*1}=\frac{40-30\sqrt{2}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+30\sqrt{2}}{2*1}=\frac{40+30\sqrt{2}}{2}
$